Y=3(-2)^2+m(-2)+8

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Solution for Y=3(-2)^2+m(-2)+8 equation: 



=3(-2)^2+Y(-2)+8

We move all terms to the left:

-(3(-2)^2+Y(-2)+8)=0



We calculate terms in parentheses: -(3(-2)^2+Y(-2)+8), so:

3(-2)^2+Y(-2)+8

determiningTheFunctionDomain
Y(-2)+8+3(-2)^2

We add all the numbers together, and all the variables

Y(-2)+20

We multiply parentheses

-2Y+20

Back to the equation:

-(-2Y+20)



We get rid of parentheses

2Y-20=0

We move all terms containing Y to the left, all other terms to the right

2Y=20

Y=20/2

Y=10

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